4x^2+12x=216

Solution for 4x^2+12x=216 equation:

4x^2+12x=216

We move all terms to the left:

4x^2+12x-(216)=0

a = 4; b = 12; c = -216;
Δ = b2-4ac
Δ = 122-4·4·(-216)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-60}{2*4}=\frac{-72}{8}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+60}{2*4}=\frac{48}{8}
=6
$